18x^2+77x+2=0

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Solution for 18x^2+77x+2=0 equation:



18x^2+77x+2=0
a = 18; b = 77; c = +2;
Δ = b2-4ac
Δ = 772-4·18·2
Δ = 5785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-\sqrt{5785}}{2*18}=\frac{-77-\sqrt{5785}}{36} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+\sqrt{5785}}{2*18}=\frac{-77+\sqrt{5785}}{36} $

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